Question

A 3-column table with 5 rows. The first column has entries empty, distance travelled (meters), time (initial) (seconds), time (final) (seconds), elapsed time (seconds), average speed (meters per second). The second column labeled Trial A has entries 4.0, 2.0, 2.5, 1.5, 2.7. The second column labeled Trial B has entries 4.0, 1.5, 4.5, empty, empty.
Use the data table on the left to complete the calculations.

What is the elapsed time for Trial B? (in seconds)
What is the average speed for Trial B?
m/s (meters/seconds)

Answer 1

Answer:

Elapsed time for Trial B is 3.0s, Average speed for Trial B is 1.3 m/s

Explanation:

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Answer 2

The elapsed time for trial B is 3 seconds and the average speed for trial B is 1.33 m/s.

Given:

data regarding 2 trials A and B as shown in the image below

To Find:

1. the elapsed time for trial B

2. the average speed for trial B

Solution:

the elapsed time is simply the difference between the final time and the initial time.

⇒ elapsed time for trial B = 4.5 - 1.5 = 3 seconds

now, the average speed is given as the total distance divided by the total time

here, the total time is the same as the elapsed time

⇒ average speed for trial B = 4/3 = 1.33 m/s

Thus, the elapsed time for trial B is 3 seconds and the average speed for trial B is 1.33 m/s.

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