a 3 digit number 24a is divisible by 9 what is the value of a
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multiples of 9 till ten
9 18 27 36 45 54 63 72 81 90
subtract the second digit of the 2 digit multiple of 9 and it should give a multiple of 9
i.e 24 - 0 = 24
24 - 1 = 23
24 - 2 = 22
24 - 3 = 21
24 - 4 = 20
24 - 5 = 19
24 - 6 = 18
24 - 7 = 17
24 - 8 = 16
Here 18 is a multiple of 9
now check the multiple of 9 having first digit 6
it's 63
therefore, a = 3
pls mark the answer as brainliest if possible
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