Question

A 3 digit number 4a3 is added to another 3 digit no 984 to give four digit number 13b7which is divisible by 11 then find a+b

Answer 1

Given 3 digit number = 4a3 and another 3 digit number = 984

ATQ

sum of 4a3 and 984 will give 13b7/ 11

first we have to check that which number we use in place 'a' so that it gave sum which will divide by 11. I check the number is 1 which we will use in place of 'a' .

now the sum of 413+ 984=1397/11

now we have the value of 'a' and 'b' which is 1 and 9 sum of a nd b is 10

hence sum of a nd b is 10