Question

A 3-digit number 4A3 is added to another 3-digit number 984 to give four digit number 13B7, which is divisible by 11. Find (A+B)

Answer 1

Answer:

According to the question

4a3+984=13b7

a+8=b

Thenb−a=8

According to the question 13b7 is divisible by 11

(7+3)−(b+1)=(9−b)

(9−b)=0

b=9

b=9anda=1

Then a+b=9+1=10

Answer 2

QUESTION:

A 3-digit number 4A3 is added to another 3-digit number 984 to give four digit number 13B7, which is divisible by 11. Find (A+B).

Given:

4A3+984=13B7

13B7 is divisible by 7

SOLUTION:

4A3

+984

=13B7

A+8=B

13B7 is divisible by 7.

1+B=3+7 (Divisibility rule of 11)

1+B=10

B=10-1

B=9

A+8=B

A+8=9

A=9-8

A=1

Therefore A=1, B=9

A+B=1+9=10

A+B=10

HOPE IT HELPS YOU;)