A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11.
Find a and b?
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Here is your answer.
a=1 and b=9
according to question 4 digit no 13b7 is divisible by 11 then (sum 0f even place)-(sum 0f odd place)=0 or any no which is divisible by 11 then
(3+7)-(1+b)=9-b by put b=9 we get 0 that means no is divisible by 11 . therefore b=9
and no is 1397 and is sum of 4a3 and984 now sustract the 984 from no we get value of a (1397-984)=413
hence a=1
a=1 and b=9
according to question 4 digit no 13b7 is divisible by 11 then (sum 0f even place)-(sum 0f odd place)=0 or any no which is divisible by 11 then
(3+7)-(1+b)=9-b by put b=9 we get 0 that means no is divisible by 11 . therefore b=9
and no is 1397 and is sum of 4a3 and984 now sustract the 984 from no we get value of a (1397-984)=413
hence a=1
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2
Step-by-step explanation:
Pythagoras of Samos ( c. 570 – c. 495 BC) was an ancient Ionian Greek philosopher and the eponymous founder of Pythagoreanism. His political and religious teachings were well known in Magna Graecia and influenced the philosophies of Plato, Aristotle, and, through them, Western philosophy.
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