A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7 which is divisible by 11. Find the value of (a+b)
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13b7 is divisible by 11.
so,(1+b)-(3+7)=? is divisible by 11
(1+b)-10=0 (3+7=10 is less than 11)
1+b=10
b=10-1=9
b=9.
4a3+984=13b7
4a3+984=1397
13(8+a)7=1397
8+a=9
a=9-8=1
a=1.
(a+b)=(1+9)=10
(a+b)=10.
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