Math, asked by dheeraj2011, 6 hours ago

A 3-digit number 4BC is divisible by 15. What are the values of B and C for the smallest such number?​

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Answered by arhamsurana42
2

Answer:

if 4BC is divisible by 15 then it must divisible by 3 and 5. and it will become 4B5. then this number also divisible by 3 so we have to add 4+B+5 and it must be a multiple of 3 . 405 is the smallest number.

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