Question

A 3 digit number is such that its tens digit is equal to the product of the other two digits which are prime. Also, the difference between its reverse and itself is 99. What is the sum of the three digits?​

Answer 1

Answer:

A 3 digit number is such that its tens digit is equal to the product of the other two digits which are prime. Also, the difference between its reverse and itself is 99. Hence, the sum of the three digits is 11 in each case.

Answer 2

The sum of the digits of the required number is 11.

Step-by-step explanation:

Step by step Explanation:

Given:-

  A 3 - digit number, product of digits is the number in the tenths place and the numbers are prime.

  Also, the difference of the reverse of the number and the number is 99.

To find:-

  The sum of the digits of the number.

Now, the prime numbers between 1 and 10 are 2,3,5 and 7.

Since, we want the product of these numbers to be the number in between.

Therefore, we will get only 2 and 3.

Now, the number can be 263 or 362 ( 2*3 = 6)

Since the number should be smaller than its reverse, (then only we will get the difference 99)

So, our desired number is 263.

The sum of its digits is 2 + 6 + 3 = 11.