A 3-digit number when divided by 10 gives a remainder 6. Also, it gives a remainder 56 when
divided by 100. If the number is between 300 and 400, find the number.
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The first valid value for x is 11.
[ 11 / 3 = 3 ‘+ 2’ ] and [ 11 / 4 = 2 ‘+ 3’ ]
The series then progresses in steps of 12
[ 23 / 3 = 7 ‘+ 2’ ], [ 23 / 4 = 5 ‘+ 3 ‘ ]
The first three digit number in this series will therefore be
8 * 12 + 11 ( the first valid number )
= 96 + 11
= 107
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