Math, asked by resha5293, 8 months ago

a)
3. Find the LCM by common division method.
a) 21. 63 and 105 b) 16, 40 and 56 c) 20,25 and 30
d) 12,32 and 36

Answers

Answered by simran18092004
1

Answer:

Which of the following are pairs of co-primes?

(i) 8, 14

(ii) 4, 5

(iii) 17, 19

(iv) 27, 15

ANSWER:

Two numbers which have only 1 as a common factor are said to be co-prime or relatively prime or mutually prime numbers.

We can write 17 as 17 × 1 and 19 as 17 × 1.

Hence, 17 and 19 is a pair of co-prime numbers.

Page No 15:

Question 3:

List the prime numbers from 25 to 100 and say how many they are.

ANSWER:

There are a total of 16 prime numbers between 25 and 100 which are 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.

Page No 15:

Question 4:

Write all the twin prime numbers from 51 to 100.

ANSWER:

If the difference between two co-prime numbers is 2, the numbers are said to be twin prime numbers.

Hence, the twin prime numbers between 51 and 100 are 59 and 61, 71 and 73.

Page No 15:

Question 5:

Write 5 pairs of twin prime numbers from 1 to 50.

ANSWER:

If the difference between two co-prime numbers is 2 then, the numbers are said to be twin prime numbers.

Hence, the twin prime numbers from 1 to 50 are (2,3), (5,7), (11,12), (17,19) and (29,30).

Page No 15:

Question 6:

Which are the even prime numbers?

ANSWER:

There is only even prime number which is 2.

Page No 17:

Question 1:

Factorise the following numbers into primes.

(i) 32

(ii) 57

(iii) 23

(iv) 150

(v) 216

(vi) 208

(vii) 765

(viii) 342

(ix) 377

(x) 559

ANSWER:

(i)

32 = 2 × 16

= 2 × 2 × 8

= 2 × 2 × 2 × 4

= 2 × 2 × 2 × 2 × 2

(ii)

57 = 3 × 19

(iii)

23 = 23 × 1

(iv)

150 = 2 × 75

= 2 × 3 × 25

= 2 × 3 × 5 × 5

(v)

216 = 2 × 108

= 2 × 2 × 54

= 2 × 2 × 2 × 27

= 2 × 2 × 2 × 3 × 9

= 2 × 2 × 2 × 3 × 3 × 3

(vi)

208 = 2 × 104

= 2 × 2 × 52

= 2 × 2 × 2 × 26

= 2 × 2 × 2 × 2 × 13

(vii)

765 = 3 × 255

= 3 × 3 × 85

= 3 × 3 × 5 × 17

(viii)

342 = 2 × 171

= 2 × 3 × 57

= 2 × 3 × 3 × 19

(ix)

377 = 13 × 29

(x)

559 = 13 × 43

Page No 19:

Question 1:

Find the HCF.

(i) 25, 40

(ii) 56, 32

(iii) 40, 60, 75

(iv) 16, 27

(v) 18, 32, 48

(vi) 105, 154

(vii) 42, 45, 48

(viii) 57, 75, 102

(ix) 56, 57

(x) 777, 315, 588

ANSWER:

(i)

HCF = 5

(ii)

HCF = 2 × 2 × 2= 8

(iii)

HCF = 5

(iv)

HCF = 1

(v)

HCF = 2

(vi)

HCF = 7

(vii)

HCF = 3

(viii)

HCF = 3

(ix)

HCF = 1

(x)

HCF = 3 × 7 = 21

Page No 19:

Question 2:

Find the HCF by the division method and reduce to the simplest form.

(i) 275525

(ii) 76133

(iii) 16169

ANSWER:

(i)

HCF = 25

∴275525=275÷25525÷25=1121

(ii)

HCF = 19

∴76133=76÷19133÷19=47

(iii)

HCF = 23

∴16169=161÷2369÷23=73

Page No 21:

Question 1:

Find the LCF.

(i) 12, 15

(ii) 6, 8, 10

(iii) 18, 32

(iv) 10, 15, 20

(v) 45, 86

(vi) 15, 30, 90

(vii) 105, 195

(viii) 12, 15, 45

(ix) 63, 81

(x) 18, 36, 27

ANSWER:

(i)

LCM = 3 × 5 × 4 = 60

(ii)

LCM = 2 × 3 × 4 × 5 = 120

(iii)

LCM = 2 × 9 × 16 = 288

(iv)

LCM = 2 × 2 × 3 × 5 = 60

(v)

LCM = 45 × 86 = 3870

(vi)

LCM = 2 × 3 × 3 × 5 = 90

(vii)

LCM = 3 × 5 × 7 × 13 = 1365

(viii)

LCM = 2 × 2 × 3 × 3 × 5 = 180

(ix)

LCM = 3 × 3 × 3 × 3 × 5 = 567

(x)

LCM = 2 × 2 × 3 × 3 × 3 = 108

Page No 21:

Question 2:

Find the HCF and LCM of the numbers given below. Verify that their product is equal to the product of the given numbers.

(i) 32, 37

(ii) 46, 51

(iii) 15, 60

(iv) 18, 63

(v) 78, 104

ANSWER:

(i)

HCF = 1

LCM = 32 × 37 = 1184

Product of two numbers = 32 × 37 = 1184

Product of HCF and LCM = 1 × 1184 = 1184

(ii)

HCF = 1

LCM = 46 × 51 = 2346

Product of two numbers = 46 × 51= 2346

Product of HCF and LCM = 1 × 2346 = 2346

(iii)

HCF = 3 × 5 = 15

LCM = 3 × 5 × 4 = 60

Product of two numbers = 15 × 60 = 900

Product of HCF and LCM = 15 × 60 = 900

(iv)

HCF = 3 × 3 = 9

LCM = 3 × 3 × 2 × 7 = 126

Product of two numbers = 18 × 63 = 1134

Product of HCF and LCM = 9 × 126 = 1134

(v)

HCF = 2 × 13 = 26

LCM = 2 × 13 × 3 × 4 = 312

Product of two numbers = 78 × 104 = 8112

Product of HCF and LCM = 26 × 312 = 8112

Page No 23:

Question 1:

Choose the right option.

(i) The HCF of 120 and 150 is ................... .

(1) 30

(2) 45

(3) 20

(4) 120

(ii) The HCF of this pair of numbers is not 1.

(1) 13, 17

(2) 29, 20

(3) 40, 20

(4) 14, 15

ANSWER:

(i)

HCF = 2 × 3 × 5 = 30

Hence, the correct answer is option (1).

(ii)

40 = 2 × 2 × 2 × 5

20 = 2 × 2 × 5

The HCF of 20 and 40 is 2 × 2 × 5 or 20.

Hence, the correct answer is option (3).

Page No 23:

Question 2:

Find the HCF and LCM.

(i) 14, 28

(ii) 32, 16

(iii) 17, 102, 170

(iv) 23, 69

(v) 21, 49, 84

ANSWER:

(i)

HCF = 2 × 7 = 14

LCM = 2 × 7 × 2 = 28

(ii)

HCF = 2 × 2 × 2 × 2 = 16

LCM = 2 × 2 × 2 × 2 × 2 = 32

(iii)

HCF = 17

LCM = 17 × 2 × 3 × 5 = 510

(iv)

HCF = 23

LCM = 23 × 3 = 69

(v)

HCF = 7

LCM = 3 × 4 × 7 × 7 = 588

Page No 23:

Question 3:

Find the LCM.

(i) 36, 42

(ii) 15, 25, 30

(iii) 18, 42, 48

(iv) 4, 12, 20

(v) 24, 40, 80, 120

ANSWER:

(i)

LCM = 2 × 2 × 3 × 3 × 7 = 252

(ii)

LCM = 2 × 3 × 5 × 5 = 105

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