Question

a 3 galloon mixture consists of one part of s and two parts of R.in order to change the mixture of 25% of S how much R should be added

Answer 1

Answer:

Explanation:

A 3-gallon mixture contains one part S and two parts R.

In order to change it to a mixture containing 25% S, how much R should be added?

:

The the resulting amt will be 75% r, do this in per cent r, ignore s

A 3 gallon mixture 1:2 will have 2%2F3r in it

:

 

let r = no. of gal of r required

the mixture equation

2%2F3(3) + r = .75(r+3)

2 + r = .75r + 2.25

r - .75r = 2.25 - 2

.25r = .25

r = 1 gallon required to accomplish this