Question

A 3 gm lead bullet at 30 ºC is fired at a speed of 240 m/s into a large block of ice at 0ºC, in which it becomes embedded. What quantity of ice melts?

Answer 1

Answer:

The bullet will not melt all the ice, so its final temperature is 0

0

C.

Then, conservation of energy gives

(

2

1

mv

2

+mc∣ΔT∣)

bullet

=m

w

L

f

where m

w

is the mass of melted ice. Solving form

w

gives,

m

w

=(

3.33×10

5

J/kg

3.00×10

−3

kg

)×[(0.500)(240m/s

2

)+(128J/kg.

0

C)(30.0

0

C)]

m

w

=

333000J/kg

86.4J+11.5J

=0.294g

Explanation:

Hope it helps mate....

Answer 2

Answer:

the final temperature is 0