A 3 hp motor required 2.4 kw to drive it. Its efficiency is about
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Answered by
12
Hello Dear.
Here is the answer---
Power of the Motor = 3 HP.
= 3 × 746 W. [Changing Horse Power into Watt]
= 2238 W.
Power Input or Required Power = 2.4 kW.
= 2400 W.
Now, Using the Formula,
Efficiency = (Power Output/Power Input) × 100%
∴ Efficiency = (2238/2400) × 100%
⇒ Efficiency = 2238/24
⇒ Efficiency = 93.25 %
Hence, Efficiency of the Motor is 93.25%.
Hope it helps.
Here is the answer---
Power of the Motor = 3 HP.
= 3 × 746 W. [Changing Horse Power into Watt]
= 2238 W.
Power Input or Required Power = 2.4 kW.
= 2400 W.
Now, Using the Formula,
Efficiency = (Power Output/Power Input) × 100%
∴ Efficiency = (2238/2400) × 100%
⇒ Efficiency = 2238/24
⇒ Efficiency = 93.25 %
Hence, Efficiency of the Motor is 93.25%.
Hope it helps.
Answered by
3
Answer:
Efficiency of motar is 93.27%
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