Question

A=[3 I -I 2] .find 'K' so that A^2 =kA-7I​

Answer 1

Answer:

Hope this will help you...

Answer 2

Step-by-step explanation:

Here

X = 3k -1, y, = k-2

X;=k, y=k-7

X3 = k-1, y = -k-2

Putting values

1 x lyn-ya) + x,(Y-Y:) + x3[v. - Y) 1 = 0

x;(Y2 - y 2) + xy - Y.) + x2(y1 - y2) = 0

(3k-1)[k-7-(K-2)] + [-k-2-(-2)] + (k-1)[(k - 2) - (k-7)] = 0

(3k - 1)Ik - 7+k+ 2] + k[-k-2-k+ 2] + (k-1)[k-2-k+ 7) = 0

(3k 1)(2k – 5) + kl-2k] + (k-1)(-2+ 7) = 0

3k(2k-5)-12k - 5) - 2k? + (k- 1)5 = 0

6k2 – 15k – 2k + 5- 2k? + 5k - 5 = 0

6k? – 2k2 – 15k – 2k + 5k + 5-5 = 0

4k2 – 12k = 0

4k(k – 3)

= 0 =

So, k = 0 and k = 3

Hopeit helps MRK ME As BRAINLIEST