a 3. In a box of 50 batteries, it is known that there are five defective batteries, what is the probability of drawing out a i) defective battery ii) non-defective battery.
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1
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Answered by
3
Answer:
Total no. of bulbs =20
No. of defective bulbs =4
Therefore,
P(getting a defective bulb)=
total no. of bulbs
No. of defective bulbs
=
20
4
=
5
1
Now,
One non defective bulb is drawn then the total numbers of bulb left is 19
Total numbers of bulbs =19
No. of defective bulbs =4=4
No. of non-defective bulbs =19−4=15
P(bulb is not defective)=
total numbers of bulbs
No. of non-defective bulbs
=
19
15
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