Question

A 3 kg ball moving straight down strikes the floor at 8
m/s. It rebounds upwards at 6 m/s. the magnitude of
change in momentum is..
plz fast it's urgent​

Answer 1

Answer:

Explanation:

Given :

• Mass (m) = 3kg
• Initial velocity (u) = 8 m/s
• Final velocity (v) = 6 m/s

To Find :

• The change in momentum of the ball.

Formula to be used :

• Momentum = Mass × Velocity
• ∆p = Pf - Pi

Solution :

Let Pi and Pf be the initial and final momentums of the ball,

★Initial momentum of the ball,

Pi = mu

⇒ Pi = 3 × 8

⇒ Pi = 24 kg.m/s

★Final momentum of the ball,

Pf = mv

⇒ Pf = 3 × 6

⇒ Pf = 18 kg.m/s

★Change in momentum of the ball,

∆p = Pf - Pi

⇒ ∆p = 18 - 24

⇒ ∆p = -6 kg.m/s

Hence, Change in momentum of the ball is -6 kg.m/s.

Answer 2

$\huge\mathcal\colorbox{red}{{\color{black}{★ANSWER★}}}$

$\huge\color{red}{\textbf{\textsf{GIVEN :-}}}$

• Mass (m) = 3 kg
• Initial velocity (u) = 8 m/s
• Final velocity (v) = 6 m/s

$\huge\color{red}{\textbf{\textsf{TO FIND :-}}}$

• The change in momentum of the ball.

$\huge\color{red}{\textbf{\textsf{FORMULA :-}}}$

• Momentum = mass × velocity
• ∆p = Pf - Pi

$\huge\color{red}{\textbf{\textsf{SOLUTION :-}}}$

Initial momentum of the ball,

Pi = mu

=> Pi = 3 × 8

=> Pi = 24 kg.m/s

Final momentum of the ball,

Pf = mv

=> Pf = 3 × 6

=> Pf = 18 kg.m/s

Change in momentum of the ball,

∆p = Pf - Pi

=> ∆p = 18 - 24

=> ∆p = -6 kg.m/s

Hence, the change in the momentum is -6 kg.m/s.

Hope it Helps Buddy ♥️