Question

A 3 kg block has a speed of 4 m/s and 8 m/s at
A and B respectively. If the distance between A
and B along the curve is 12 m, then calculate the
magnitude of frictional force acting on the block.
Assuming the same friction, how far away from B
the block will stop?

IRRELEVANT ANSWERS WILL BE REPORTED​

Answer 1

Answer

• Frictional force is -6 N and Distance will be 4 m

Explanation

Given

• Mass of the block = 3 kg
• Initial Velocity = 4 m/s
• Final Velocity = 8 m/s
• Distance Between the blocks = 12 m

To Find

• Frictional Force on the body
• The distance at which block B will stop at

Solution

• First find an expression for acceleration, then use the third equation of motion to find the frictional force and then the distance will be given by the formula s = v²/2a

✭ Acceleration (equation)

→ F = ma

→ a = F/m

✭ Frictional Force

→ v²-u² = 2as

→ 4²-8² = 2×a×12

→ 16-64 = 2× (F/m) × 12

→ -48 = 24(F/m)

→ -48/24 = F/3

→ -2 = F/3

→ -2×3 = F

→ Force = -6 N

✭ Acceleration

→ a = F/m

→ a = -6/3

→ a = -2 m/s²

✭ Distance Covered

→ s = v²/2a

→ s = 4²/2×2

→ s = 16/4

→ s = 4 m

Answer 2

$\huge{\boxed{\rm{\red{Question}}}}$

A 3 kg block has a speed of 4 m/s and 8 m/s at A and B respectively. If the distance between A and B along the curve is 12 m, then calculate the magnitude of frictional force acting on the block. Assuming the same friction, how far away from B the block will stop?

$\huge{\boxed{\rm{\red{Answer}}}}$

${\bigstar}\large{\boxed{\sf{\pink{Given \: that}}}}$

• Mass of the block = 3 kg
• Initial velocity = 4 m/s
• Final velocity = 8 m/s
• Distance between the block = 12 m

${\bigstar}\large{\boxed{\sf{\pink{To \: find}}}}$

• Frictional force on the body.The distance at which block B will stop at.

${\bigstar}\large{\boxed{\sf{\pink{Full \: Solution}}}}$

${\bigstar}\large{\boxed{\sf{\pink{Acceleration \: equation}}}}$

↝ Firstly find an expression for acceleration then the third equation of the motion to find the frictional force then the distance will be given by the formula that is given below ↔

$\bold{\blue{\fbox{\green{s = v² / 2a}}}}$

↝ A = f/m

↝ A = -6 / 3

↝ A = -2 m/s²

${\bigstar}\large{\boxed{\sf{\pink{Covered \: distance}}}}$

↝ s = 4² / 2a

↝ s = 4²/2×2

↝ s = 16 / 4

↝ s = 4 m

$\large\red{\texttt{4 m is the answer}}$

@Itzbeautyqueen23

Hope it's helpful

Thank you :)