Question

A 3 kg bomb explodes into 3 equal pieces A, B and C. A
flies with a speed of 40 m/s and B with a speed of 30 m/s
making an angle of 90° with the direction of A. The angle
made by the direction of C with that of A is​

Answer 1

Answer:- Check from pic ☝

Answer 2

Answer:

Linear momentum is conserved before and after explosion.

The bomb is at rest before it explodes. So, the initial momentum is zero.

Let's say the piece A moves along positive x-axis, and the piece B along positive y-axis. And let's assume that the piece C is moving at an angle of  θ  with the negative x-axis at a speed of v.

Conserving along the x-axis

0 = 1 ( 40 )-1 ( v cos θ)

vcosθ = 30

From these two equations,

tanθ = 3/4

cosθ = 4/5

So,piece C makes an angle of π-cosθ-1 4/5with piece A