Question

A 3 kg cake is divided into 3 pieces whose weights are in the ratio 7:3:5. What is the weight of the 2nd piece in gm ?

Answer 1

Answer:

3kg 3000gm

let the first piece be 7x

second piece be 3x

third piece be 5x

atq,

7x+3x+5x=3000gm

15x=3000gm

x=3000/15=200gm

so,weight of second piece=3x=3*200=600gm

Answer 2

Step-by-step explanation:

$\mathbf\red{Given:-}$

• A 3kg cake is divided into 3 pieces
• The ratio of the weights of pieces of cake = 7:3:5

$\mathbf\blue{To\:Find}$

• The weight of the 2nd piece of the cake in grams

$\mathbf\green{Solution}$

$\tt\pink{Weight\:of\:the\:whole\:cake= 3kg}$

$\tt\pink{Weight\:in\:grams = 3×1000 = 3000\: grams}$

Given, Ratio = 7:3:5

$\tt\orange{Sum\: of\: the\: ratio= 7+ 3 + 5 = 15}$

$\tt\purple{ Weight\:of \: {1}^{st} \: piece = \frac{7}{15} \times 3000}$

$\tt\purple{= 7×200 \implies 1400\: grams}$

_______________

$\tt\red{Weight\: of \: {2}^{nd}\: piece = \frac{3}{15} \times 3000}$

$\tt\red{=3×200 \implies 600\: grams}$

_______________

$\tt\blue{Weight\:of\:{3}^{rd}\: piece \frac{5}{15} \times 3000}$

$\tt\blue{= 5×200 \implies 1000\: grams}$

________________

$\boxed{Weight\: of\: {2}^{nd} \: piece = 600\: grams}$