A 3 kg load is suspended vertically by a 6 kg rope. The tension at the upper end of the spring will be
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For horizontal equilibrium-
T
3
=T
1
sinθ
For vertical equilibrium-
T
2
=T
1
cosθ
Taking ratios-
T
2
T
3
=tanθ
And for equilibrium of body T
2
=6kgwt=6×10=60N
⟹tanθ=
6
5
or θ=tan
−1
6
5
Follow the given picture
T
3
=T
1
sinθ
For vertical equilibrium-
T
2
=T
1
cosθ
Taking ratios-
T
2
T
3
=tanθ
And for equilibrium of body T
2
=6kgwt=6×10=60N
⟹tanθ=
6
5
or θ=tan
−1
6
5
Follow the given picture
Attachments:
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