Physics, asked by Jzero, 1 month ago

A 3 kg load is suspended vertically by a 6 kg rope. The tension at the upper end of the spring will be ​

Answers

Answered by manishgupta8462
3

Explanation:

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Answered by Vermaaryan15
0
For horizontal equilibrium-

T
3

=T
1

sinθ

For vertical equilibrium-

T
2

=T
1

cosθ

Taking ratios-

T
2


T
3



=tanθ

And for equilibrium of body T
2

=6kgwt=6×10=60N

⟹tanθ=
6
5



or θ=tan
−1

6
5






Follow the given picture
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