Question

a 3 m wide path runs outside around a rectangular park it's length 125m and breadth 65 m find the area of path

Answer 1

Let ABCD be the given park.

Then ABCD is the inside of path and EFGH is the outside of path.

 

also PA = DQ = DR = CS = 3 m  (width of path)

Now EH = PQ = PA + AD + DQ = 3 m + 125 m + 3 m = 131 m

and HG = RD + DC + CS = 3m + 65 m + 3 m = 71 m

 

we know that area of rectangle = Length × breadth

⇒ Area of garden (ABCD) = AD × DC = 125 m × 65 m = 8125 m2

and Area of EFGH = EH × HG = 131 m × 71 m = 9301 m2

 

Hence area of path = Area of EFGH – Area of ABCD

= 9301 m2 – 8125 m2 = 1176 m2