.A 3 m wide road runs around a circular park whose circumference is 132 m. Find the cost of fencing the outer boundary of the road at the rate of Rs84 per sq.m. (take pi =22/7)
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Circumference = 2πr = 176
π = 22 / 7
2πr = 44r / 7 = 176
r = 7 x 176 / 44
r = 28m
Since, the road is 7m wide and a fence is to be put on the outer boundary, the new radius (r) becomes 7 + 28, which is 35m.
Therefore, circumference = 2 x π x 35
= 2 x 22 x 35 / 7
= 2 x 22 x 5
= 220m
The rate of fencing is Rs. 21 per m
Thus, the cost of fencing = 21 x 220
= Rs. 4620
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