Question

A
3
Solve any one sub question.
i) In ABC, AP=3, PB =9, BC = 15, AQ = x
and QC =y. Give any two pairs of values
ofx and y such that line PQ || side BC.
​

Answer 1

Answer:

10

Step-by-step explanation:

Since PQ∥BC,

Thus using Basic Proportionality Theorem

QC

AQ

=

PB

AP

⇒

x

5

=

6

3

⇒3x=30, cross multiply

∴x=10