A 3 times magnified image of both nature was
produced by a concave mirror of focal length 12 cm.
Determine the object and image distance from the
missor for both real and image..
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Answer:
u= -8 cm & v=24 cm
Explanation:
-v/u=3 (given)
or -v=3u
or v=-3u
f= -12 cm
Putting the above values in the mirror formula:
1/v+1/u=1/f
or 1/-3u + 1/u = 1/-12
or -1+3/3u = 1/-12 [taking 3u as LCM]
or 2/3u=-1/12
or 3u = -24
or u=-24/3
or u= -8 cm
We know, v=-3u
Now v=-3*-8
or v=24 cm
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