Question

A 3 V battery is connected across a 5 ohms resistance the heat produced in 5 second is?
​

Answer 1

H = I ² R t --------------------------------(1)

=> V = IR

=> 3V = I × 5

=> I = 3 / 5

on putting the value in equation 1 we get

H = i² Rt

=> (3 / 5)² × 5 × 5

=>. 9 / 25 × 25

=> 9 Joule

hence , heat energy will produce => 9 Joule

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Answer 2

Answer:

Heat produced , H=I

2

Rt

here,

t

H

5

=I

5

2

R

5

=10⇒I

5

=

5

10

=

2

. This is the current through resistor 5Ω.

Voltage across resistor 5Ω is V

5

=I

5

R

5

=

2

×5=5

2

V

As resistors (4,6) and 5 are in parallel, so potential across (4,6) is equal to V

5

.

As resistor 4 and 6 are in series so current through each resistor I

4

=I

6

=

4+6

V

5

=

4+6

5

2

=

2

2

Heat produce in resistor 4 per sec =I

4

2

R

4

=(

2

2

)

2

×(4)=2cal/sec

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