Physics, asked by NayyarSultana, 11 months ago

A 30 g bullet is fired horizontally with velocity 250m/s from a 1.5 kg gun. If the gun is held loosely in hand, its recoil velocity would be_?​

Answers

Answered by rishabh1213
21

m1 = mass of gun  m2 = mass of bullet

formula

m1u1+m2u2=m1v1+m2v2

here initial velocity of both gun and bullet is 0

so m1v1=-m2v2

now 1500g*v1=30*250

v1=30*250/1500

so v1 = 5m/s is the answer negative indicates in opposite direction

thankyou


NayyarSultana: thank u fa helping
rishabh1213: welcome
Answered by aliyasubeer
3

Answer:

Recoil velocity will be -5ms⁻¹.

Explanation:

Concept:

  • Recoil velocity is the speed at which the stock of the rifle impacts your shoulder.
  • According to the law of conservation of momentum, the total momentum of the gun and the bullet will be zero after the gun is fired. Let m be the mass of the bullet and v be the velocity on firing the gun; M is the mass of the gun and V be the velocity with which it recoils.

                                             MV+mv=0

Given:

Mass of bullet, m=30g= .03kg( 1Kg=1000g)

Velocity of bullet, v=250ms⁻¹

Mass of gun, M=1.5kg

Recoil velocity of gun =V

Description:

  • Before firing, the system (gun+bullet) is at rest, initial velocity =0
  • So initial momentum of the system =0
  • Final momentum of the system = momentum of bullet + momentum of gun

                                                    =mv+MV

                                                    = .03×250+1.5×V

                                                    =7.5+1.5V

  • According to law of conservation of momentum, Final momentum = Initial momentum.

                                                   7.5+1.5V=0

                                                   1.5V=−7.5

                                                          or        

                                                       V=−7.5/1.5

​                                                           =−5ms⁻¹

Note: The direction of recoil velocity of the gun is opposite to the direction of the velocity of the bullet. That's why the sign of recoil velocity is negative.

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