Question

A 30 gram bullet travelling at 120 m/s penetrates 12 cm into a wooden block. Find the average resistance exerted by the wooden block.

Answer 1

30 grams = 0.030 kg

Initial velocity = 120 m/s

Final velocity = 0 m/s

Distance convered = 12 cm = 0.12 m

Acceleration =

${v}^{2} = {u}^{2} + 2as \\ {0}^{2} = {120}^{2} + 2 \times a \times 0.12 \\ - 14400 = 0.24 \times a \\ a = - \frac{ 14400}{0.24} \\ a = - \frac{ 1440000}{24} \\ a = - \frac{ 120000}{2} \\ a = - 60000 \: m {s}^{ - 2}$

Force = mass × acceleration

$= 0.030 \times ( - 60000) \\ = \frac{30}{1000} \times - 60000 \\ = 30 \times - 60 \\ = - 1800 \: newtons$

Force applied by the wooden block will be 1800 Newtons.

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Answer 2

Answer:

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Explanation: