Question

A 30 kg box has to move up an inclined plane of slope 30o to the horizontal with a uniform velocity of 5m^-1. If the frictional force retarding the box is 150N, the horizontal force needed to move the box up is (g=10m/s^2)?

Answer 1

Answer:

F = 300N

Explanation:

*refer to attachment*

Force of friction = 150N

Net horizontal force,

F - f = m.g. sinө

F = m.g. sin30°+ f

F = 30 * 10 * 1/2 + 150

F = 150 + 150

F = 300N

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Answer 2

Question

A 30 kg box has to move up an inclined plane of slope 30° to the horizontal with a uniform velocity of 5m^-1. If the frictional force retarding the box is 150N, the horizontal force needed to move the box up is (g=10m/s^2)?

Answer

Given :-

Mass = 30 kg

gravity = 10 ms

Force = 150 N

To Find :-

The horizontal force needed to move the box up

Solution

The horizental force FH is given by

FH = Mg sine Φ + F

FH = (30) (10) sin 30 ° + 150

FH = 150 + 150 = 300 N

Hence,

the horizontal force is 300 N .