A 30 kg boy who has fallen into a hole is being lifted by a helicipter with a rope which can with a maximum force of 60 kgf. With what maximum acceleration should the helicopter rise so that the rope does not snape? (Take g= 9.8m/sec^2)
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Explanation:
1kgf=9.8N
60kgf=60×9.8=588N force of helicopter
588=30×a=a=19.6m/s^2
acceleration due to gravity =9.8
so accleration of helicopter needed=19.6-9.8=9.8m/s^2
Answered by
0
Answer:
Explanation:
1kgf=9.8N
60kgf=60×9.8=588N force of helicopter
588=30×a=a=19.6m/s^2
acceleration due to gravity =9.8
so accleration of helicopter needed=19.6-9.8=9.8m/s^2
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