A 30 kg boy who has fallen into a hole is being lifted by a helicipter with a rope which can with a maximum force of 60 kgf. With what maximum acceleration should the helicopter rise so that the rope does not snape? (Take g= 9.8m/sec^2)
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Answered by
18
This shows that tension in the string should not be more 60N
weight of boy=30kg
max. force with which ,boy can be lifted up=maximum tension in the string=60N
60=30×a(max.)
a=2
this shows that,boy can move up with Max. acceleration of 2
so,for the boy to rise,,the maximum acceleration of t helicopter=2m/sec^2
{Hope it helps}
Answered by
2
This shows that tension in the string should not be more 60N
weight of boy=30kg
max. force with which ,boy can be lifted up=maximum tension in the string=60N
60=30×a(max.)
a=2
this shows that,boy can move up with Max. acceleration of 2
so,for the boy to rise,,the maximum acceleration of t helicopter=2m/sec^2
{Hope it helps}
Thanks!!!!!!
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