Question

A 30 kg fly wheel is moving with uniform angular acceleration. if radius of fly wheel is 2m then its moment of inertia:​

Answer 1

Given ,

mass = 30 kg

radius = 2 m

We know that , the moment of inertia is given by

I = mr²

Substitute the known values , we get

I = 30 × (2)²

I = 30 × 4

I = 120 kg•m²

Hence , the moment of inertia is 120 kg•m²

Answer 2

Concept:

A body's moment of inertia, or resistance to having its speed of rotation about an axis changed by the application of torque, is a quantitative measure of its rotational inertia (turning force).

The angular acceleration, which is frequently denoted by the symbol and stated in radians per second per second, is the rate at which the angular velocity changes over time.

Given:

The mass of the wheel is $30kg$.

The radius of the wheel is $2m$.

Find:

The moment of inertia of the flywheel.

Solution:

The flywheel of $30kg$ is moving with angular acceleration and the radius of the wheel is $2m$.

$m=30kg,r=2m$

The moment of inertia is given as:

I = mr²

$I=(30)(2)^2\\I=30(4)\\I=120kg.m^2$

The moment of inertia of the flywheel is $120kg.m^2$.

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