Question

A 30 kg shell is flying at 48 velocity when it explotes its one part of 18 kg stop while the remaining part flied on. Find the velocity of the later.

Answer 1

Answer:

120

Explanation:

initial momentum = MV

final momentum = $m_{1}v_{1} + m_{2}v_{2}$

given that $v_{1} = 0\\and\\m_{1} = 18Kg\\So\\m_{2} = 30-18 = 12Kg$

conservation of momentum implies that

initial momentum = final momentum

MV = $m_{1}v_{1} + m_{2}v_{2}$

put values we get

MV = $m_{2}v_{2}$

$v_{2}=\frac{MV}{m_{2}}=\frac{48 * 30}{12}=120$

Answer 2

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