A 30-kilogram mass is resting on a rough, horizontal surface. A horizontal force of 100N is required just to start it moving. What is the approximate value for the coefficient of static friction?
Answers
Answered by
1
Answer:
=μsN
where F_sFs =friction force
NN = normal force
\mu_sμs = coefficient of static friction
which can be written as;
\frac{F}{mg}=\mumgF=μ
where F= force
m= mass
g= gravity
\mu=μ= coefficient of friction
substituting the given values in the equation
\frac{100}{30\times10}=\frac{1}{3}30×10100=31
Coefficient of static friction = 1/3
Similar questions