a 30 m high pole was standing at a point of the length side of rectangular garden.of the angles of elevation of that pole from the end points of that breadth are found 60 degree and 30 degree , find the length of that garden
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so we get
CB (Distance from tree) = 5m
∠BCA = 60°
Right angle is at point B
AB (Height) = ?
A right angle triangle △ ABC is formed in which
AB is the Opposite Side from angle of elevation
BC is the Adjacent Side from angle of elevation
We know that Tan θ = Opposite Side / Adjacent Side
tan 60° = AB
BC
√ 3 = AB
10
AB = 10 x √ 3
Value of √ 3 is 1.73 so,
AB = 5 x 1.73 = 8.65
AB = 8.65m is the height of tree
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