A 30-N/C uniform electric field points perpendicularly toward the left face of a large neutral conducting sheet. The surface charge density in C/m2 on the left and right faces, respectively, are
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Given :
Electric field E = 30N/C
To find :
The surface charge density in C/m² on the left and the right faces respectively.
Solution :
Electric field E = 30N/C
Electric field for a infinite sheet :
E = σ / ε₀
30N/C = σ / (8.854 × 10⁻¹² C²/Nm²)
σ = (30N/C)(8.854 × 10⁻¹² C²/Nm²)
σ = 265.6 × 10⁻¹² C/m²
σ = 2.7 × 10⁻⁹ C/m²
Due to induction of charge
Left face of the sheet negative charge
So, σ = - 2.7 × 10⁻⁹ C/m²
Right face of the sheet positive charge
So, σ = 2.7 × 10⁻⁹ C/m²
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0
Answer:
-5.31x10e-10 , +5.31x10e-10
Explanation:
As for infinite sheet of charge E=σ/2е₀
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