A 30 W heater keeps 600g of molten metal at its melting pt. The heater is switched off and the temp. starts falling after 6 mins. Calculate specific latent heat of fusion of the metal.
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Heat energy lost in 6 min can be given as
Q =Pt=306×60=0.0833 JThis heat energy keeps 600 gm metal at melting point.SoQ = mLL =Qm=0.0833 J600=1.39×10−4 J/g
Q =Pt=306×60=0.0833 JThis heat energy keeps 600 gm metal at melting point.SoQ = mLL =Qm=0.0833 J600=1.39×10−4 J/g
harshitsinghunnnao:
mark brainliest
plzzz
isnt P×T = 60 × 6×60= 10800J
sry...P×T = 30×6×60=10800J
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