Physics, asked by prathamtiwari6645, 10 months ago

A 300 m long train corsses a platform in 39sec. While it corsses a signal pole in 18sec . What is length of platform

Answers

Answered by Blaezii
67

Answer :

The length of the platform is 350 meter.

Explanation :

Given that :

A 300 m long train corsses a platform in 39 sec.

It corsses a signal pole in 18 sec.

To Find :

The length of the platform.

Solution :

We know that :

\bigstar\;\boxed{\sf Speed = \dfrac{Distance}{Time}}}

So,

\sf \\ \\\implies Speed = \left(\dfrac{300}{18}\right)m/sec.

\sf \\ \\\implies \dfrac{50}{3}m/sec

\star\;\textbf{\underline{\underline{Consider as -}}}

The length of the platform as - 'x metres'

Then,

\sf\\ \\\implies \left(\dfrac{x+300}{39}\right)\\ \\ \\\implies \dfrac{50}{3}\\ \\ \\\implies 3(x+300)=1950\\ \\ \\\implies x=350m.

The length of the platform is 350 meter.

\rule{300}{1.5}

\bigstar\;\textbf{\underline{\underline{Extra Information:}}}

Speed :

The measure of something that how fast or slow is this called Speed.

Acceleration  :

The capacity of the vehicle to gain speed is called its Acceleration.

Velocity :

The speed of something in a given direction is called its Velocity.

Answered by BrainlyWriter
64

 \bold {\huge {Answer :-}}

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯

✦ ✬Given

➛Length of train = 300 m

➛Time taken to cross the platform = 39 sec

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯

✦ ✬To find

➛The length of Platform when it cross a signal in 18 sec

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯

Since we know,

\huge{\boxed{\boxed{Speed = \frac{Distance}{time}}}}

\bold{\Rightarrow\:Speed=\frac{300}{18}}

\bold{\Rightarrow\:Speed=\frac{50}{3}\:\:\:m/sec}

\bold{→Therefore, \:the\:speed\:of\:train\:is\:\frac{50}{3}\:\:\:m/sec}

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯

⇨ Now let be the length of platform be x

⇨ Therefore the speed when it cross the poles is

\bold{\Rightarrow\:Speed=\frac{x+300}{39}\:\:\:m/sec}

→We know that train is travelling in constant speed hence the speed will be same for both cases.

\bold{\Rightarrow\:\frac{50}{3} =\frac{x+300}{39}\:\:\:m/sec}

\bold{\Rightarrow\:50\:\times\:39= 3(x+300)}

\bold{\Rightarrow\:x= 350 \:m}

Hence, the length of platform is 350 m

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