Math, asked by wwwneela03, 8 months ago

A 300 metre long train crosses an electric pole in 15 seconds. In how many seconds will it cross a bridge 0.6km long?

Plz give the step by step solution

Answers

Answered by Anonymous
2

\red{\tt{\underline{\underline{Answer:}}}}

\sf{The \ train \ will \ take \ 7.5 \ minutes}

\sf{to \ cross \ the \ bridge.}

\orange{\tt{\underline{\underline{Given:}}}}

\sf{\implies{Length \ of \ train=300 \ m}}

\sf{\implies{Train \ crosses \ a \ pole \ in \ 15 \ seconds}}

\pink{\tt{\underline{\underline{To \ find:}}}}

\sf{How \ long \ will \ take \ to \ cross}

\sf{bridge \ of \ 0.6 \ km}

\blue{\tt{\underline{\underline{Solution:}}}}

\sf{Speed=\frac{Distance}{Time}}

\sf{\therefore{Speed=\frac{300}{15}}}

\sf{\therefore{Speed=20 \ m \ s^{-1}}}

\sf{1 \ km=1000 \ m}

\sf{0.6 \ km =600 \ m}

\sf{Here,}

\sf{\implies{Speed=20 \ m \ s^{-1}}}

\sf{\implies{Distance=600+300=900 \ m}}

\sf{Time=\frac{Distance}{Time}}

\sf{\therefore{Time=\frac{900}{20}}}

\sf{\therefore{Time=450 \ seconds}}

\sf{60 \ seconds=1 \ minute}

\sf{\frac{450}{60}=7.5 \ minutes}

\sf\purple{\tt{\therefore{The \ train \ will \ take \ 7.5 \ minutes}}}

\sf\purple{\tt{\therefore{to \ cross \ the \ bridge.}}}

Answered by TheSentinel
44

\huge\underline\mathfrak\blue{Answer}

\rm\pink{Time \ taken \ by \ the \ train \ to \ cross }

\rm\pink{a \ bridge \ 0.6 km \ long : 45 sec}

__________________________________________

\sf\large\underline\orange{Given:}

\rm{Length \ of \ the \ train :300 m}

\rm{Time \ by \ the \ train \ to \ cross \ the \ electric \ pole}

\rm{ :15 sec}

__________________________________________

\sf\large\underline\orange{To \ find:}

\rm{Time \ taken \ by \ the \ train \ to \ cross }

\rm{a \ bridge \ 0.6 km \ long}

__________________________________________

\huge\underline\mathfrak\green{Solution:}

speed =  \frac{distance}{time}

speed =  \frac{300}{15}

speed = 20 m {s}^{ - 1}

0.6km = 600m

\rm{</strong><strong>here</strong><strong>,</strong><strong>}

distance = 300  +  600

distance = 900m

time =  \frac{distance}{speed}

time =  \frac{900}{20}

time = 45sec

\rm</strong><strong>\</strong><strong>p</strong><strong>i</strong><strong>n</strong><strong>k</strong><strong>{Time \ taken \ by \ the \ train \ to \ cross }

\rm</strong><strong>\</strong><strong>p</strong><strong>i</strong><strong>n</strong><strong>k</strong><strong>{a \ bridge \ 0.6 km \ long</strong><strong> </strong><strong>:</strong><strong> </strong><strong>4</strong><strong>5</strong><strong> </strong><strong>sec</strong><strong>}

__________________________________________

\</strong><strong>r</strong><strong>m</strong><strong>\</strong><strong>r</strong><strong>e</strong><strong>d</strong><strong>{</strong><strong>hope</strong><strong> </strong><strong>\</strong><strong> </strong><strong>it</strong><strong> </strong><strong>\</strong><strong> </strong><strong>helps</strong><strong> </strong><strong>}</strong><strong> :))

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