Question

A)300 rev
B)600 rev
C)200 rev
D)900 rev

Answer 1

Heya!!

_____________________________✨✨✨

→Given,

W° = 1800 rpm = 1800/60 =30 rotations

W=0

time = 20sec

so, apply

w =w° + alpha t

0= 30 + alpha × 20

alpha =-3/2 rotations /sec

( NOTE →

∆ = angular displacement here)

∆ = W° t + 1/2 alpha t^2

∆ = 30 × 20 + 1/2 (-3/2) × 20 ×20

∆ = 600-300

= 300 rotations

correct answer is option( 1)

hope it helps!!

PhoeniXX

Answer 2

Answer:

Heya!!

_____________________________✨✨✨

→Given,

W° = 1800 rpm = 1800/60 =30 rotations

W=0

time = 20sec

so, apply

w =w° + alpha t

0= 30 + alpha × 20

alpha =-3/2 rotations /sec

( NOTE →

∆ = angular displacement here)

∆ = W° t + 1/2 alpha t^2

∆ = 30 × 20 + 1/2 (-3/2) × 20 ×20

∆ = 600-300

= 300 rotations

correct answer is option( 1)

hope it helps!