Physics, asked by Anonymous, 4 days ago

A 3000 kg car moving at a speed of 72km/hr , applies brakes and come to rest in 4seconds.Find the force applied by brakes to bring it to rest




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Answers

Answered by tiwarivirendra286
2

Answer:

You need to convert first 72 km/h to m/s.

Converting 72 km/h to m/s

72 km/h = 72000 m / 3600 s

72 km/h = 720/36 m/s

72 km/h = 20m/s

Next step is to solve for the needed time to stop the car using t = v / a

t = v / a

t = 20 m/s / 5 m/s^2

t= 20/5 s

t = 4 s

It needs 4 s to stop the car.

Answered by jhas25959
1

Answer:

The car applied the force on the brakes 15000 Newton

Explanation:

mass of car = 3000 kg

speed of car = 72km/hr

time = 4 seconds

find the force

we use a formula

F = ma

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