A 3000 kg car moving at a speed of 72km/hr , applies brakes and come to rest in 4seconds.Find the force applied by brakes to bring it to rest
Gud eve..
@sab here
anyone alive
Answers
Answered by
2
Answer:
You need to convert first 72 km/h to m/s.
Converting 72 km/h to m/s
72 km/h = 72000 m / 3600 s
72 km/h = 720/36 m/s
72 km/h = 20m/s
Next step is to solve for the needed time to stop the car using t = v / a
t = v / a
t = 20 m/s / 5 m/s^2
t= 20/5 s
t = 4 s
It needs 4 s to stop the car.
Answered by
1
Answer:
The car applied the force on the brakes 15000 Newton
Explanation:
mass of car = 3000 kg
speed of car = 72km/hr
time = 4 seconds
find the force
we use a formula
F = ma
Similar questions