Question

A 3000 kg truck is on a cliff and is tied with a rope to a 78 kg person hanging over the cliff. If the cliff is very icy (frictionless), what is the magnitude of acceleration of the system?

[Question from Laws of Motion☺]

[Draw FBD and Solve the question; No attachment!!]

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Answer 1

Answer:

From FBD of truck

T−m1a=0

T=m1a=3000a……(i)

FBD of man

m2g−T=m2a

78g−T=78a

Putting the value of T from Eq. (i)

78g-3000a=78a

3078a=78g

a = 78×103078

a = 0.25ms-²

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