A 3000 kg truck is on a cliff and is tied with a rope to a 78 kg person hanging over the cliff. If the cliff is very icy (frictionless), what is the magnitude of acceleration of the system?
[Question from Laws of Motion☺]
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Answer:
From FBD of truck
T−m1a=0
T=m1a=3000a……(i)
FBD of man
m2g−T=m2a
78g−T=78a
Putting the value of T from Eq. (i)
78g-3000a=78a
3078a=78g
a = 78×103078
a = 0.25ms-²
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