Question

A 3000 kg truck moving at a speed of 90 m/s stops after covering some distance. The force applied by brakes is 27000 N. Compute the distance covered and work done by this force.​

Answer 1

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Answer 2

$\huge\bold\purple{Bonjour!!}$

$\huge\mathfrak{Solution:-}$

⏩ Here,

* u= 90 m/s,

*v = 0,

*F = -27000 N,

*m = 3000 kg

We know that, F = ma

= a = F/m

=> - 27000/3000

=> -9 m/s²

Also, v² - u² = 2as

=> 0² - (90)² = 2(-9)s

=> s = 450 m.

Now,

W= F × s

= -27000 × 450

= -12150000 J

= -12150 kJ (The required solution)

[-ve sign shows the retarding force]

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