A 3000 kg truck starts from rest and rolls down a hill with constant acceleration. It travels a distance of 400.0 m in the first 25.0 s. Calculate the net force on the truck. Round your answer to the nearest whole number.
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Answer is 3840N
dist. = 1/2at^2
from this equation we get acceleration
a=800/625m/s^2
now Force=Mass*acceleration
= 3000*800/625
=3840N
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