Question

a 300g copper calorimeter containing 500g of water is at 15°c. a 560g copper ar at 99°c is then dropped into the calorimeter. the final temperature of the system is 22.5°c. assuming no heat loss, calculate the specific heat capacity of copper​

Answer 1

Solution,

Mass of copper calorimeter (M1) = 300g = 0.3kg

Specific heat capacity of water (S2) = 4200 joule per kg degree kelivin

Mass of aluminium block(M) = 560g = 0.56 kg

Mass of water(Mw) = 0.5 kg

Temperature of water + calorimeter (k1)=15 degree celsius

Specific heat capacity of calorimeter(S1) = 390 joule per kg degree celsius

Temperature of aluminium block (k2) = 100 degree celsius

Temperature of mixture (k)= 22.5 degree celsius

Now,

Total heat lost by aluminum block

=Ms(k2-k)

=0.56*s(100-22.5)

=43.4s

we know,

heat gained by calorie

=M1*S1(k-k1)

=0.3*390(22.5-15)

=877.5

Heat gained by water

=M2S2(k-k1)

=0.5*4200*(22.5-15)

=15750

Total Heat Gained

=15750+877.5

=16627.5

Now,

Heat gained = heat lost

43.4s=16627.5

s=383.12 joule per kg degree celsius.