Question

a) 301z4 is a multiple of 9, where 'z' is a digit. Find the value of 'z'.
b) Given that the number 35a64 is divisible by 3, where 'd' is a digit. Find all possible
values of 'd'?​

Answer 1

Answer:

a)Given that 301z5 is a multiple of 9.  

According to the divisibility rule of 9, the sum of all the digits should be a multiple of 9.  

Therefore,  

3+0+1+z+5=9 OR 18

⇒z=9−9=0

⇒z=18−9=9

b)The sum of digits of a number divisible by 3 is a multiple of 3

3+5+a+6+4=3n  

18+a=3n  

If n=6⇒3n=18

If n=9,3n=27

If n=6,7,8,9⇒18+a=18,21,24,27  

∴a=0,3,6,9

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