Question

A 30g bullet initially travelling at 500m/s penetrates 12 CM a wooden block.What average force does it exert?

Answer 1

Given that:

• Mass of a bullet = 30g
• Velocity = 500 m/s
• Distance = 12 cm

Need to find:

• Average force does it exert = ?

Solution:

From work - energy theorem

${\qquad}{\bigstar{\boxed{\sf{ \frac{1}{2}m {v}^{2} = f.s}}}}$

According to the question —

$\sf \implies \: f = \frac{m {v}^{2} }{2s } \\ \\ \sf \implies \: f = \frac{30 \times {10}^{ - 3} \times {(500)}^{2} }{2 \times 12 \times {10}^{ - 2} } \\ \\ \sf \implies \: f = 31250 \: newton$

Hence,Average force will be 31250 N.