Question

A 30g bullet leaves a riffle with a velocity of 300m/sec and the riffle recoils with velocity of 0.6m/sec. find the mass of the rifle

Answer 1

Given:

• Mass of bullet = 30 g = 0.03 kg
• Velocity of bullet = 300 m/s
• Recoil velocity = 0.6 m/s

To find:

Mass of rifle ?

Calculation:

Since, there is no external force on the system, the net linear momentum will remain constant.

$m_{b}u_{b} + m_{g}u_{g} = m_{b}v_{b} + m_{g}v_{g}$

• m_(g) is mass of gun, m_(b) is mass of bullet.

Now, initial velocity of both bullet and gun is zero.

$\implies 0 + 0 = m_{b}v_{b} + m_{g}v_{g}$

$\implies 0 + 0 = (0.03 \times 300) + m_{g}( - 0.6)$

$\implies m_{g} = \dfrac{9}{0.6}$

$\implies m_{g} = 15 \: kg$

So, mass of rifle is 15 kg.

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Answer 2

The mass of the rifle is, 15 kg.

What is the mass?

• Mass, in physics, quantitative measure of inertia, a fundamental property of all matter.
• It is, in effect, the resistance that a body of matter offers to a change in its speed or position upon the application of a force.
• The greater the mass of a body, the smaller the change produced by an applied force.

According to the question:

Given:

Mass of bullet = 30 g = 0.03 kg

Velocity of bullet = 300 m/s

Recoil velocity = 0.6 m/s

Calculation:

Since, there is no external force on the system, the net linear momentum will remain constant.

$m_{b} u_{b}+m_{g} u_{g}=m_{b} v_{b}+m_{g} v_{g}$

m_(g) is mass of gun, m_(b) is mass of bullet.

Now, initial velocity of both bullet and gun is zero.

$0+0=m_{b} v_{b}+m_{g} v_{g}\\0+0=(0.03 \times 300)+m_{g}(-0.6)\\m_{g}=\frac{9}{0.6}\\m_{g}=15 \mathrm{~kg}$

Hence, mass of rifle is 15 kg.

Learn more about mass here,

https://brainly.in/question/47883246?msp_poc_exp=5

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