Question

a 30gm bullet initially travelling at 120m/sec penetrates 12cm into a wooden block . the average resistance exerted by the wooden block is ?​

Answer 1

30grams =0.030 kg

intial velocity =120m/s

Final velocity =0m/s

distance covered =12cm =0.12m

acceleration

${v}^{2} = {u}^{2}$

${0}^{2} = {120}^{2} + 2 \times a \times 0.12$

$- 14400 = 0.24 \times 2a$

$a = \frac{1440 2 }{0.24}$

$a = \frac{1440000}{24}$

$a = \frac{120000}{2}$

$a = 60000ms { - }^{2}$

$force = mass \times accleration$

$0.030 \times ( - 600000)$

$\frac{30}{1000} \times 60000$

$30 \times - 60$

$1800newtons$

Force applied by the Wooden block will be 1800newtons

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