Question

A 325 mL sample of gas is initially at a pressure of 721 torr and a temperature of 32°C. If this gas is compressed to a volume of 286 mL and the pressure increases to 901 torr, what will be the new temperature of the gas (reported to three significant figures in °C)?

Answer 1

V1=325 ml                                                                          V2=286 ml

P1= 721 torr                                                                        P2= 901 torr

T1= 32+273 K => 305 K                                                    T2=?

By gas Equation:

P1V1/T1=P2V2/T2

721*325/305=901*286/T2

234325/305=257686/T2

T2=257686*305/234325

T2=78594230/234325

T2=335.4069 K

T2=335.4069-273 C

T2=62.4068

T2=62.4°C