Question

A 325-N force accelerates a 50.0-kg crate from rest along a horizontal frictionless surface for a distance of 20.0 m as shown in the figure.

What coefficient of friction would be required to keep the crate moving at constant speed under the action of the 325-N force?Immersive Reader

Answer 1

Explanation:

When the body is moving with constant velocity , then acceleration is 0.

Force - Friction = Mass × Acceleration

325 - Friction = 0

Frictional force = 325 N

$\alpha mg = frictional \: force$

$\alpha = coefficient \: of \: friction$

m = Mass of the crate

g = acceleration due to gravity

$\alpha mg = 325$

$\alpha (50)(10) = 325$

$\alpha = 0.65$

Therefore , it is your answer.

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